By Dr. A. C. Thompson

ISBN-10: 0408013915

ISBN-13: 9780408013918

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Sample text

YS HOME : VTAB 24 HGR : HCOL0R= 3 FOR I = 1 TO NP 42 Potential flow fundamentals 2070 2080 2090 2100 2110 2200 2210 2220 2230 2240 2250 XI = X 2 ( I ) * SF + XS Y1 = YS - Y 2 ( I ) * SF I F I = 1 GOTO 2200 HPLOT TO X1,Y1 GOTO 2210 HPLOT X1,Y1 NEXT I X1 = X 2 ( 1 ) * SF + XS Y1 = YS - Y 2 ( 1 ) * SF HPLOT TO X1,Y1 RETURN 3000 3010 3020 3025 3026 3030 3040 3050 3060 3066 3067 3070 3080 3090 3100 3110 3200 3220 3250 3260 3270 3280 3290 3300 REH VEL. ON SURFACE INPUT "ANGLE OF FLOU? ";AF INPUT "CIRCULATION 6/2PI?

The velocities on the new shape are then found by calculating the potential gradients along the surface working in an anticlockwise direction round the shape. Having found potential and velocity we can work out the pressures as explained in the next section. Program TRANC1 100 110 120 130 140 145 150 160 170 180 190 200 210 215 216 220 230 240 250 260 270 300 1000 1010 1020 1030 1040 1050 1060 1070 1080 1090 1100 2000 2010 2020 2030 2040 2050 2060 DIN X2(100),Y2(100),P2(100),V2(100 INPUT "RADIUS?

Suppose our fluid particle moves from x, y to (x + Ax, y + Ay) where the velocity in the jc-direction is u + (du/dx) Ax + (du/dy) Ay. 14 Definitions for total acceleration This, and the equation in the y-direction for dp/dy, could be integrated to find the pressure at a point B, starting from point A. However, we can simplify this integration by using some results from potential flow. Since the flow is irrotational and u can be related to velocity potential by u = dfy/dx. 16) and a similar equation in the y-direction can be derived.

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Basic Hydrodynamics by Dr. A. C. Thompson


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